Integrating functions in python

| categories: math, python | tags:

Matlab post

Problem statement

find the integral of a function f(x) from a to b i.e.

$$\int_a^b f(x) dx$$

In python we use numerical quadrature to achieve this with the scipy.integrate.quad command.

as a specific example, lets integrate


from x=0 to x=1. You should be able to work out that the answer is 1/3.

from scipy.integrate import quad

def integrand(x):
    return x**2

ans, err = quad(integrand, 0, 1)
print ans

1 double integrals

we use the scipy.integrate.dblquad command

Integrate \(f(x,y)=y sin(x)+x cos(y)\) over

\(\pi <= x <= 2\pi\)

\(0 <= y <= \pi\)


\(\int_{x=\pi}^{2\pi}\int_{y=0}^{\pi}y sin(x)+x cos(y)dydx\)

The syntax in dblquad is a bit more complicated than in Matlab. We have to provide callable functions for the range of the y-variable. Here they are constants, so we create lambda functions that return the constants. Also, note that the order of arguments in the integrand is different than in Matlab.

from scipy.integrate import dblquad
import numpy as np

def integrand(y, x):
    'y must be the first argument, and x the second.'
    return y * np.sin(x) + x * np.cos(y)

ans, err = dblquad(integrand, np.pi, 2*np.pi,
                   lambda x: 0,
                   lambda x: np.pi)
print ans

we use the tplquad command to integrate \(f(x,y,z)=y sin(x)+z cos(x)\) over the region

\(0 <= x <= \pi\)

\(0 <= y <= 1\)

\(-1 <= z <= 1\)

from scipy.integrate import tplquad
import numpy as np

def integrand(z, y, x):
    return y * np.sin(x) + z * np.cos(x)

ans, err = tplquad(integrand,
                   0, np.pi,  # x limits
                   lambda x: 0,
                   lambda x: 1, # y limits
                   lambda x,y: -1,
                   lambda x,y: 1) # z limits

print ans

2 Summary

scipy.integrate offers the same basic functionality as Matlab does. The syntax differs significantly for these simple examples, but the use of functions for the limits enables freedom to integrate over non-constant limits.

Copyright (C) 2013 by John Kitchin. See the License for information about copying.

org-mode source

Discuss on Twitter